Beam Deflection Calculator

Beam deflection = 5 × w × L⁴ ÷ (384 × E × I) for a uniform load on a simple span: two 2x10s of Douglas fir-larch No. 2 carrying 100 plf over 12 ft sag 0.15 in, about L/977.

Units
Load
plf

Floor psf × tributary width, plus the beam itself.

Span
ft
in

E = 1,600,000 psi

Section
Plies nailed together

Simple span, uniform load, 12 ft

0.15in

That is L/977: stiff enough for a floor.
12 ft0.15 in
Deflection drawn exaggerated. Dashed line: the beam before loading.
Max moment
1,800 lb-ft
Max shear
600 lb
Bending stress
505 psi

Against common sag limits

  • Limit L/180 0.80 in

    Rafters with no ceiling, IRC R802.4.1(1)

  • Limit L/240 0.60 in

    Ceiling joists, IRC R802.5.1

  • Limit L/360 0.40 in

    Floor joists, IRC R502.3.1

  • Limit L/480 0.30 in

    Stricter than the IRC tables

Deflection is only one check. A beam also has to carry the bending and shear, bear on its supports and stay braced sideways. For anything that holds up a floor, roof or wall, have an engineer verify it. This is bending deflection only; shear deflection is not included.
The math
  1. Section

    2 × 2×10, 3 × 9.25 in = I = 197.9 in⁴

  2. Stiffness

    E × I = 1,600,000 psi × 197.9 in⁴ = 317 × 10⁶ lb-in²

  3. Deflection formula

    5 w L⁴ ÷ (384 E I) = 0.15 in

  4. Ratio

    12 ft ÷ 0.15 in = L/977

Beam deflection is 5 × w × L⁴ ÷ (384 × E × I) for a uniform load on a simple span: two 2x10s of Douglas fir-larch No. 2 carrying 100 plf over 12 ft sag 0.15 in, about L/977. Pick the supports and the load, a material and a section above, and the calculator gives the sag, the L/ ratio, the largest moment and shear, and the deflected shape.

How beam deflection is calculated

Deflection depends on four things: the load, the span, the stiffness of the material (its modulus of elasticity E, in psi) and the stiffness of the cross section (its moment of inertia I, in in⁴). The formulas below are from the American Wood Council's Design Aid No. 6, and they hold for any material as long as the beam stays elastic.

Simple span, uniform load: Δ = 5 × w × L⁴ ÷ (384 × E × I). Simple span, center load: Δ = P × L³ ÷ (48 × E × I). w in lb per inch, P in lb, L in inches.

The section stiffness of a solid rectangle is I = width × depth³ ÷ 12. That cube is why depth matters so much: a 2x12 (11¼ in deep) has 1.8 times the I of a 2x10 (9¼ in) for the same width.

Worked example: two 2x10s over 12 ft

Two 2x10 plies are 3 in wide and 9¼ in deep, so I = 3 × 9.25³ ÷ 12 = 197.9 in⁴. Douglas fir-larch No. 2 has E = 1,600,000 psi. A uniform load of 100 plf is 8.33 lb per inch, and the span is 144 in.

Δ = 5 × 8.33 × 144⁴ ÷ (384 × 1,600,000 × 197.9) = 0.147 in, which is L/977. That passes every common limit. The largest moment is w × L² ÷ 8 = 21,600 lb-in (1,800 lb-ft) and the largest shear 600 lb.

Beam deflection formulas for every case

For the same uniform load, the supports change the sag a lot. Compared with a simple span of the same length, load and section:

Supports, uniform loadMaximum deflectionCompared with a simple span
Simple span5 w L⁴ ÷ 384 E I1.00
Cantileverw L⁴ ÷ 8 E I9.6
Fixed at both endsw L⁴ ÷ 384 E I0.20
Fixed at one end, supported at the otherw L⁴ ÷ 185 E I0.42

With a point load: simple span, center P L³ ÷ 48 E I; simple span with two equal loads at the third points P a (3 L² − 4 a²) ÷ 24 E I with a = L ÷ 3; cantilever, load at the free end P L³ ÷ 3 E I; fixed at both ends, center P L³ ÷ 192 E I; fixed at one end and supported at the other, center 0.009317 P L³ ÷ E I. A 2x10 (one ply, 1.6 million psi) with a 200 lb load at the end of a 4 ft cantilever sags 0.047 in.

Modulus of elasticity of common materials

Values in psi from published design tables:

MaterialE, psiSource
Structural steel29,000,000AISC 360-16
2.0E LVL2,000,000Weyerhaeuser TJ-9000
Douglas fir-larch No. 21,600,000AWC design values
Southern pine No. 21,400,000AWC design values
Spruce-pine-fir No. 21,400,000AWC design values
Hem-fir No. 21,300,000AWC design values
MDF grade 130313,000Composite Panel Association

The calculator also carries sugar maple, red and white oak, walnut, poplar and cherry from the USDA Wood Handbook, and lets you enter your own E from a data sheet. Steel is about 18 times stiffer than Douglas fir at the same section, but no one uses the same section: use the steel beam calculator to size one.

How much sag is too much

The IRC span tables limit floor joists to L/360, ceiling joists to L/240 and rafters without a finished ceiling to L/180. The calculator checks your sag against each and against L/480, a stricter limit for brittle finishes. A 12 ft floor beam allowed L/360 may sag 0.40 in. Long-term creep in wood adds to the sag shown here, so keep some margin.

Next questions

Deflection is one check of three; bending strength and shear also have to pass, and shear deflection is not included here. Have an engineer verify any beam that holds up a floor, roof or wall.